If tan(A+B)=3\tan (A + B) = \sqrt{3}tan(A+B)=3 and tan(A−B)=13\tan (A - B) = \dfrac{1}{\sqrt{3}}tan(A−B)=31; 0∘<A+B≤90∘0^\circ < A + B \le 90^\circ0∘<A+B≤90∘; A>BA > BA>B, find AAA and BBB.