In Fig. 6.39, riangle ABC and riangle AMP are two right triangles, right angled at B and M respectively. Prove that: (i) riangle ABC \sim riangle AMP (ii) \dfrac{CA}{BC} = \dfrac{PA}{MP}

Question

In Fig. 6.39, $	riangle ABC$ and $	riangle AMP$ are two right triangles, right angled at $B$ and $M$ respectively. Prove that:
**(i)** $	riangle ABC \sim 	riangle AMP$
**(ii)** $\dfrac{CA}{BC} = \dfrac{PA}{MP}$

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